Question 170862

{{{y=2x^2-3x+1}}} Start with the given equation.



Notice we have a quadratic equation in the form of {{{y=ax^2+bx+c}}} where {{{a=2}}}, {{{b=-3}}}, and {{{c=1}}}



Since {{{a>0}}} (ie "a" is positive), this tells us that the parabola opens upward and the function has a minimum.