<PRE><B>Question 170669</B>
{{{(-2a^2b^3)^2/(2a^2b)^3}}}
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I&#39;m not sure how you got that answer, but let&#39;s just go thru it.
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You multiply the numerator exponents by 2; (-2^2 = +4)
Multiply the denominator exponents by 3 (2^3=8) and we have
{{{(4a^4b^6)/(8a^6b^3)}}}
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Combine the exponents of like terms, in a manner to ensure they are positive:
{{{(b^((6-3)))/(2a^((6-4)))}}} = {{{b^3/(2a^2)}}}
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did this make sense to you?</PRE>