Question 2882
 Since log3 x^2 = 2 log3 x,
 (log3 x)^2 = log3 x^2 + 3 converts to

 (log3 x)^2 - 2log3 x - 3 = 0.

 Let u = log3 x, we have u^2 - 2u -3 =0,
 Factoring (u-3)(u+1) =0,
 So, u =3 or -1. 
 Hence, log3 x = 3,u = 3^3 = 27 or
 log3 x = -1,u = 3^(-1) = 1/3