Question 170746
he seems to be simply comparing the ratios of 2/8 and 1/4 and paying no attention to the x terms........one way to prove he is wrong is to find the lcd...which is 8 in this case. once the denominators are equal we can compare the numerators
:
{{{(2+x)/8}}}.....eq 1

{{{(1+x)/4}}}--->..eq 2 multiply top and bottom by 2--->{{{2(1+x)/8}}}={{{(2+2x)/8}}}
:
clearly 2+x is not equal to 2+2x