<PRE><B>Question 170720</B>
I am having doubts that I solved this problem correctly. Here is my work.
(square root of x + 2) - 2 = (square root of x + 9)
i squared both sides.
x + 9 = x + 2 - (14square root of x + 2) + 49
9 = 51 -(14square root of x + 2)
-42= square root of x + 2
1764 = x + 2
x = 1762 
when I substitute 1762 into the original equation and found it to be extraneous. Is this correct? 
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sqrt(x + 2) - 2 = sqrt(x + 9)
Square both sides
x+9 = (x+2) +4 -4sqrt(x+2)
-4sqrt(x+2) = x+9 -x-2 -4 = 3
Square again
16*(x+2) = 9
x+2 = 9/16
x = -23/16
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It does check if you take into account the + and - on the sqrts.




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