Question 23876
You can use the "distance" formula {{{d = sqrt((x2-x1)^2 + (y2-y1)^2)}}} to solve this.
(3, 5) = (x1, y1) and
(-2, 1) = (x2, y2)

{{{d = sqrt((-2-3)^2 + (1-5)^2)}}}
{{{d = sqrt((-5)^2 + (-4)^2)}}}
{{{d = sqrt(25 + 16)}}}
{{{d = sqrt(41)}}}
{{{d = 6.4}}} approximately.