Question 170700
{{{2x+2=5sqrt(x)}}}lets square both sides to get rid of the radical{{{(5sqrt(x))^2=25x)}}}
:
{{{(2x+2)^2=25x}}}
:
{{{4x^2+8x+4=25x}}}
:
{{{4x^2-17x+4=0}}}

answer:---{{{system(x=4,x=.25)}}}

*[invoke quadratic "x", 4, -17, 4]