Question 170662
lets call the 4 pieces a,b,c,and d

a=b..........eq 1
c=4a.........eq 2
d=3b+5.......eq 3
a+b+c+d=53...eq 4
:
lets chang c's value in eq 2 to c=4b because of eq 1....now take a's value from eq 1 c's revised value from eq 2, and d's value from eq 3 and plug them into eq 4.
:
b+b+(4b)+(3b+5)=53....solve for b
:
9b=48
:
{{{highlight(b=48/9=16/3)}}}in
{{{highlight(a=b=16/3)}}}in
{{{highlight(c=4(16/3)=64/3)}}}in
{{{highlight(d=3(16/3)+5=21)}}}in