Question 170625
Solve the following problem: The sum of the squares of two consecutive positve even integers is 340. Find the integers.
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x^2 + (x+2)^2 = 340
x^2 + x^2 + 4x +4 = 340
2x^2 + 4x + 4 = 340
x^2 + 2x -168 = 0
(x-12)*(x+14) = 0
x = 12
x = -14
It's 12 and 14, since it said positive.
12*12 + 14*14 = 340, so it's correct.