Question 170430
lets call the 3 numbers a, b, and c
:
a+b+c=33...eq 1
b=a-7......eq 2
c=3b.......eq 3---->c=3(a-7)---->c=3a-21
:
take b's value in eq 2 and c's value in eq 3 and plug them into eq 1
:
a+(a-7)+(3a-21)=33
:
5a=61
:
{{{a=61/5}}}
{{{b=61/5-35/5=26/5}}}
{{{c=3(26/5)=78/5}}}