Question 170426
{{{(7-1/(2a))/(5+1/(2a))=(7(2a)-(1/cross(2a))cross(2a))/(5(2a)+(1/cross(2a))cross(2a))=(14a-1)/(10a+1)}}}



Note: in the second step, I multiplied EVERY term by the inner LCD "2a" to clear out the inner fractions.


So {{{(7-1/(2a))/(5+1/(2a))=(14a-1)/(10a+1)}}} where {{{a<>0}}} or {{{a<>-1/10}}}