Question 170409
Solve the following equation. Show all your work. 
2log9(2x+5)-1=0
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I'll assume it's log base 9
{{{2log(9,(2x+5))-1=0}}}
{{{2log(9,(2x+5)) = 1}}}
{{{log(9,(2x+5)^2) = 1}}}
Both sides are exponents of 9
{{{(2x+5)^2 = 9}}}
2x+5 = 3 or -3
2x = -2 and -8
x = -1 and -4