Question 170386
AREA=PI*R^2
AREA=3.14(8/2)^2
AREA=3.14*4^2=3.14*16=50.24 IN^2 IS REQUIRED FOR EACH LAYER.
9*50.24=452.16 IN^2 IS THE TOTAL AREA TO BE TOPPED.
452.16/54=8.37 RECIPES WILL BE REQUIRED FOR ALL 9 LAYERS.