Question 170375
Kindly explain how to resolve the following logarithmic equation
1) 1 - log (x - 2) = log (3x + 1) 
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1 - log(x - 2) = log(3x + 1)
1 = log(3x+1)-log(x-2)
1 = log((3x+1)/(x-2)) Subtracting a log --> dividing by
Raise 10 to both sides
10 = (3x+1)/(x-2)
10*(x-2) = 3x+1
10x-20 = 3x+1
7x = 21
x = 3
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