Question 170300
Hello, I tried to solve the equation 5(square root)x + 1 = 3 by doing 5(sq root) x = 3 and (5(sq. rt.) x) ^ 5 = 3^5 and I my answer is x=243
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Do you mean 5*sqrt(x+1) = 3 ?
If so,
Square both sides
25*(x+1) = 9
25x+25 = 9
25x = -16
x = -16/25
If that's not what you meant, you'll have to be more specific.