Question 170236
solve by completing the square. 3x^2+12x-9=0
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3x^2+12x-9=0
Divide by 3
x^2 + 4x - 3 = 0
x^2 + 4x = 3
(x+2)^2 = x^2+4x+4, so add 4
x^2 + 4x + 4 = 3+4
(x+2)^2 = 7
x+2 = +sqrt(7)
x+2 = -sqrt(7)
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x = -2+sqrt(7)
x = -2-sqrt(7)
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Just for grins:
*[invoke solve_quadratic_equation 1,4,-3]