Question 170226
2. Find the product of the cube of (-4/3) and square of (-3/2). 
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= (-4/3)^3*(-3/2)^2 

= -64/3^3 * 3^2/4

Cancel 3^2 in the numerator and the denominator to get:

= -64/3 * 1/4

Cancel 4 in the numerator and the denominator to get:

= -16
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Cheers,
Stan H.