Question 170214
Since the perimeter of any rectangle is:
width + width + length + length
2(width) + 2(length)
2(width + length)
.
Let w = width of rectangle
then because "length of a rectangle is three times its width"
3w = length of rectangle
.
2(width + length) <= 112
plugging in our variables above:
2(w + 3w) <= 112
2(4w) <= 112
8w <= 112
w <= 112/8
w <= 14 centimeters (width)
.
Solution: greatest possible width is 14 centimeters