Question 170178
Simplify:
1) {{{2y+3-(1/3)(6x+9y)+x = 2y+3-2x-3y+x}}}={{{-y-x+3}}}
2) {{{5x+0(x+y)-3y+14-3(y-x) = 5x-3y+14-3y+3x}}}={{{8x-6y+14}}}
Remember that zero times anything is always zero, so: 0(x+y) = 0