Question 170041
{{{x^2+y^2=25}}}
{{{3x^2+2y^2=59}}}
:
Multiply the 1st equation by 2 and subtract from the 2nd equation:
{{{3x^2+2y^2=59}}}
{{{2x^2+2y^2=50}}}
--------------------subtraction eliminates y^2
x^2 = 9
x = {{{sqrt(9)}}}
x = +/-3
:
Find y
{{{3^2+y^2=25}}}
{{{9+y^2=25}}}
{{{y^2=25-9}}}
y^2 = 16
y = {{{sqrt(16)}}}
y = +/-4
:
:
Check solutions in 2nd equation
{{{3(9)+2(16)=59}}}