Question 23796
Because it is a difference of two squares 
you could factor it as [(a+b)^2+(a-b)^2][(a+b)^2-(a-b)^2]
I'm going to called this [1st part][2nd part].
You can factor the 2nd part because it is the difference 
of two squares to get:
[(a+b)+(a-b)][(a+b)-(a-b)]
= [2a][2b]
Now, what about that 1st part?!!
If you expand it you get the following:
 (a^2+2ab+b^2)+(a^2-2ab+b^2)
Adding you get 2a^2 + 2b^2
So, putting the pieces together you have:
[2a^2+2b^2][2a}{2b]
I'll let you figure out what you want to 
do with that.  It can be simplified in 
several ways but not significantly.

Cheers,
Stan H.