Question 170017
x^2+ 3x = 4

Begin by subtracting 4 from both sides and equating to zero.

x^2 + 3x - 4 = 0

We now factor the left side.

x^2 + 3x - 4 becomes (x - 1)(x + 4).

We now set each factor to zero and solve for x.

x - 1 = 0

x = 1

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x + 4 = 0

x = -4

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Final answer: x = 1 and x = -4