Question 169185
Please help. 
Solve: 
a) 4^x-6 = 16^x 
4^x - 6 = 4^2x
4^2x - 4^x + 6 = 0
This is a quadratic in (4^x).  Sub x for 4^x, because the solver only uses x.
*[invoke solve_quadratic_equation 1,-4,6]
4^x = 2 + i*sqrt(2)
4^x = 2 - i*sqrt(2)
I'll have to do some research on that one.
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If you repost it, maybe someone else can help.  I wouldn't be optimistic, tho.
Make sure there's not a typo somewhere, too.

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b) e^-2x = 0.3 
-2x = ln(0.3)
-2x = -1.204
x = 0.602