Question 169470
</pre><font size=4><b>
Let {{{x}}}= Joe's Age
Then, {{{x-6}}}=John's Age
Therefore,
{{{x+x-6=26}}}, EQN 1 (sum of their ages)
Continuing,
{{{2x=26+6}}}
{{{2x=32}}} ---> {{{cross(2)x/cross(2)=cross(32)16/cross(2)}}}
{{{highlight(x=16yrs)}}}, Joe's Age
{{{16-6=highlight(10yrs)}}}, John's Age
Check Via Eqn 1:
{{{16+10=26}}}
{{{26=26}}}
Thank you,
Jojo</pre>