Question 169931
{{{6*root(5,5y)-2*root(5,5y)}}} Start with the given expression



Let {{{z=root(5,5y)}}}



{{{6z-2z}}} Replace {{{root(5,5y)}}} with "z"



{{{4z}}} Combine like terms.



{{{4*root(5,5y)}}} Plug in {{{z=root(5,5y)}}}



So {{{6*root(5,5y)-2*root(5,5y)=4*root(5,5y)}}}