Question 169512
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This follows the Ideal Gas Law -----> {{{PV=nRT}}}, Working Eqn
where--->{{{system(P=pressure(atm),V=13.3(L),highlight(n=moles(mass/MW)),R=GasConstant=0.0821,T=temperature(K)=90+273.15)}}}
Highlighted above is not given, so we have to calculate:
Look thru Table of Elements or Periodic Table and you find Molecular Weight for Argon: {{{39.948(g/mol)}}} 
So, {{{n=m/MW=545(cross(g))/(39.948*cross(g)/mol)}}}
{{{n=13.64mol}}}, Subst. in our Working Eqn:
{{{P(13.3)=(13.64)(0.0821)(90+273.15)}}}
{{{P(13.3)=406.67}}} ------> {{{P*cross(13.3)/cross(13.3)=cross(406.67)30.58/cross(13.3)}}}
{{{highlight(P=30.58atm)}}}, Answer
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Thank you,
Jojo