Question 169895
Solve for x using the quadratic formula:{{{x = (-b+-sqrt(b^2-4ac))/2a}}}
{{{(1/3)x^2+(2/9)x-1 = 0}}} First, multiply through by the LCD (9) to clear the fractions.
{{{3x^2+2x-9 = 0}}} Now you have: a = 3, b = 2, and c = -9.  Make these substitutions into the quadratic formula:
{{{x = (-2+-sqrt(2^2-4(3)(-9)))/2(3)}}} Simplify.
{{{x = (-2+-sqrt(4-(-108)))/6}}}
{{{x = (-2+-sqrt(112))/6}}}
{{{x = -(2/6)+sqrt(16*7))/6}}} or {{{x = -(2/6)-sqrt(16*7)/6}}} and these can be simplified to:
{{{x = -(1/3)+(2/3)sqrt(7)}}} or {{{x = -(1/3)-(2/3)sqrt(7)}}}