Question 169878
Let {{{x}}}= amount inv. @ 12%
So, {{{600000-x}}}=amount inv. @ 8%
It follows:
{{{0.12x+0.08(600000-x)=52000}}}, EQN 1
{{{0.12x+48000-0.08x=52000}}}
{{{0.04x=52000-48000=4000}}}
{{{cross(0.04)x/cross(0.04)=cross(4000)100000/cross(0.04)}}}
x=100,000 ---------> amount inv. @ 12%
.
{{{600000-100000}}}=500,000 -------> amount inv.@8%
Let's check using Simple Annual Interest:
{{{I=Prt}}}
{{{I[8]=500000*.08*1}}}=40,000
{{{I[12]=100000*.12*1}}}=12,000
Therefore,{{{I[8]+I[12]=I}}}
{{{40000+12000=52000}}}
{{{52000=52000}}}
Thank you,
Jojo