Question 169502
log3+1/2logx-log5 this becomes
log3+logx^1/2-log5 since( alogb=logb^a)
log{(3*x^1/2)/5}since[loga+logb=logab],and [loga-logb=log(a/b)]
hence the answer is 
log{(3*x^1/2)/5}