Question 169870
Solve the radical equation. 
(x-2)√(x-3)=3

sqrt(x-3) = 3/(x-2)
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Square both sides to get:
x-3 = 9/(x-2)^2

(x-2)^2(x-3) = 9

(x^2-4x+4)(x-3) = 9
x^3 -3x^2 -4x^2 + 4x -12x -12 = 9
x^3 -7x^2 -8x -21 = 0
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x = 8.2737
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Cheers,
Stan H.