Question 169537
    A photo is 3 inches longer that it is wide. A 2-inch border is placed around the photo making the total area of the photo and border 108 square inches. What are the dimensions of the photo? 
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Let w = width of photo
then
w+3 = length of photo
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If a 2-inch border is added:
width is:
w+2+2 = w+4
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length is:
w+3+2+2 = w+7
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(w+4)(w+7) = 108
w^2 + 7w + 4w + 28 = 108
w^2 + 11w + 28 = 108
w^2 + 11w - 80 = 0
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Factoring we get:
(w+16)(w-5) = 0
w = {5, -16}
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We can toss out the negative solution so we get:
w = 5 inches (width)
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Length:
w+3 = 8+3 = 11 inches (length)