Question 169844
1. Simplify
(2x^7y^2/4xy^3)^3 I know that 2/4 is 1/2 but I do not know how to simplify the exponents inside the parenthesis or the cubed exponent on the outside of the parenthesis. 
(2x^7y^2/4xy^3)^3 

=(2/4)^3*(x^7/x)^3*(y^2/y^3)^3

= (1/2)^3*(x^6)^3*(1/y)^3

= (1/8)*x^18*1/y^3

= [x^18]/[8y^3]

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2. I have no idea where to begin on this problem
If 2x + 2 is >= 5x + 11 then? How do you solve this problem.
Subtract 2x from both sides to get:
2 >=3x + 11
Subtract 11 from both sides to gt:
-9 >= 3x
Divide both sides by 3 and reverse direction of the inequality to get:
x <=-3
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Cheers,
Stan H.