Question 169824
Let {{{m[1]}}} be the slope of the line through (-3,-3) and (5,2).  Then


{{{m[1]=(-3-2)/(-3-5)=-5/-8=5/8}}}


If line {{{L[1]}}} has a slope {{{m[1]}}} and line {{{L[2]}}} has a slope {{{m[2]}}}, {{{L[1]}}} is perpendicular to {{{L[2]}}} if and only if {{{m[1]=-(1/m[2])}}} 


Since the slope of the line through (-3,-3) and (5,2) is {{{5/8}}}, the slope of any perpendicular must be {{{-(8/5)}}}; Answer A, in this case.