Question 169761
sqrt(2w^2-3w-4)=sqrt(w^2+6w+6)
squaring both sides we get:
2w^2-3w-4=w^2+6w+6
2w^2-w^2-3w-6w-4-6=0
w^2-9w-10=0
(w-10)(w+1)=0
w-10=0
w=10 ans.
w+1=0
w=-1 ans.
Proof:
sqrt(2*10^2-3*10-4)=sqrt(10^2+6*10+6)
sqrt(2*100-30-4)=sqrt(100+60+6)
sqrt(200-34)=sqrt(166)
sqrt(166)=sqrt(166)