Question 169742
How do you know you have what you have? You have a 'function of t' for interval x to x+c (I*z=c).You have b=x/z and z*r^b times the sum of the parts that follow, as i is 0 to I-1,r^i. What you need to see is that r=a^z(only positive to non-integer exponents)and you have z*a^x times the sum of the parts that follow,as i is 0 to I-1,(a^i)^z which totals to (z*a^x*(a^c-a))/(a^z-1).So you see you are summing rectangles involved with 'function t=a^t' for t=i*z+x.And do you see that the difference of f(u) for u=t+z and u=t,divided by z is a^t when f(u) z*a^u/(a^z-1)?.And also a^t is same as (for all intents and purposes?)sum of the parts that follow ,as j=0 to sufficient,t^j*log(a)^j/ j!. ( (e^t)^log(a)) is a^t.If had 'desk top' for symbols standard in mathematics mighthave made this prettier? yours truly Michael Ali unemployed bascically for all my life and broke so are u sure you want to bother learning things i may be expert in regard to?