Question 169708
Note: {{{sqrt(2)}}} is read "square root of 2"



{{{sqrt(3)(2-3*sqrt(2))}}} Start with the given expression



{{{sqrt(3)(2)-sqrt(3)(3*sqrt(2))}}} Distribute



{{{2*sqrt(3)-3*sqrt(3)sqrt(2)}}} Rearrange the terms.



{{{2*sqrt(3)-3*sqrt(3*2)}}} Combine the radicals. Note: {{{sqrt(3)sqrt(2)=sqrt(3*2)}}}



{{{2*sqrt(3)-3*sqrt(6)}}} Multiply



So {{{sqrt(3)(2-3*sqrt(2))=2*sqrt(3)-3*sqrt(6)}}}