Question 169689
A rectangular parking lot is 100ft longer than it is wide. Determine the dimensions of the parking lot if it measures 500ft diagonally. 
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Let the width be "x" ft.
Then the lengthis "x+100" ft
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Use Pythagoras to solve for "x":
x^2 + (x+100)^2 = 500^2
2x^2 + 200x + 10000 - 500^2 = 0
x^2 + 100x + 5000 - 250*500 = 0
x^2 + 100x - 120000 = 0
x = [-100 +- sqrt(100^2-4*-120000)]/2
Positive solution:
x = 300 ft. (width)
x+100 = 400 ft.(length)
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Cheers,
Stan H.