Question 169644
 solve using the quadratic formula. I can do the first few steps. I am completely lost on the math involved between the last two steps.
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{{{3x^2=-12x-1}}}
{{{3x^2+12x+1 = 0}}}
*[invoke solve_quadratic_equation 3,12,1]
Ignore what the solver says about the factors, it's not right unless the coefficient of the x^2 term is 1.
The solutions are:
-2 + sqrt(33)/3
-2 - sqrt(33)/3