<PRE><B>Question 169645</B>
what is an equation for the line perpendicular to the equation x+2y=8 going through the point (4,0)
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Find the slope, m, of the line by putting it in the slope-intercept form, y = mx+b.
x+2y=8
2y = -x+8
y = (-1/2)x + 4 so the slope is -1/2
Then, y-y1 = m*(x-x1) where (x1,y1) is the point (4,0)
y-0 = (-1/2)*(x-4)
y = (-1/2)x + 2  slope-int form
x + 2y = 4  standard form
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