Question 169585
remember the difference of cubes is a3 – b3 = (a – b)(a2 + ab + b2) eq 1

so lets take our problem and rewrite it as (2x)^3-3^3 where a is 2x and b is 3

so substitute those values in the right side of eq 1

(2x-3)(2x^2+6x+9) is our answer.