Question 169378
lets call the small field a.  So the one field is a+1 and the largest field is a+3. remember these are square fields
:
so we have  {{{a^2+(a+1)^2+(a+3)^2=38}}} distribute the left side
:
{{{a^2+a^2+2a+1+a^2+6a+9=38}}} now combine like terms
:
{{{3a^2+8a+10=38}}} subtract 38 from both sides
:
{{{3a^2+8a-28=0}}} now quadratic equation gives us

a=2 and -4.6666....so throw out the negative and we have 
:
{{{highlight(a=2)}}} smallest field
{{{highlight(a+1=3)}}} middle field
{{{highlight(a+3=5)}}} large field