Question 169287
The inverse of a 2x2 matrix, [A], defined by
{{{(matrix(2,2,a,b,c,d))}}}
is given by
{{{DELTA*(matrix(2,2,d,-b,-c,a))}}}
where
{{{DELTA=(1/(ad-bc))}}}
.
.
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In your case,
{{{DELTA=(1/((-6)(-8)-5(15)))}}}
{{{DELTA=(1/(48-75))}}}
{{{DELTA=-(1/27)}}}
{{{-(1/27)*(matrix(2,2,-8,-15,-5,-6))}}}
{{{(matrix(2,2,8/27,15/27,5/27,6/27))}}}
{{{(matrix(2,2,8/27,5/9,5/27,2/9))}}}