Question 169392
Since it's a triangle you know that,
{{{A+B+C=180}}}
{{{A+90+20=180}}}
{{{A=70}}}
I'm assuming that b is the side across from angle B.
Since one of the angle is 90 degrees, it's a right triangle and
{{{a^2+b^2=c^2}}}
Also from trig,
{{{sin(20)=b/c}}}
{{{tan(20)=a/c}}}
{{{sin(20)/cos(20)=(b/c)/(a/c)=b/a}}}
{{{tan(20)=b/a}}}
{{{a=b/tan(20)}}}
{{{a=10/tan(20)}}}
{{{a=10/0.36397}}}
{{{a=27.47}}}
and from above,
{{{a^2+b^2=c^2}}}
{{{(27.47)^2+10^2=c^2}}}
{{{754.86+100=c^2}}}
{{{c^2=854.86}}}
{{{c=29.24}}}
Angles to the nearest degree,
A=70
B=20
C=90
Sides to the nearest tenth,
a=27.5
b=10
c=29.2