Question 169258
{{{(175)^(1/3)/(50)^(1/3)}}}  {{{(25^(1/3)(7)^(1/3))/25^(1/3)/2^(1/3)}}}

{{{25(1/3)}}} cancel each other out and you end up with
:
cube root of 7 over cube root of 2.  {{{7^(1/3)/2^(1/3)}}}