Question 169202
Let x = amount of 12% acid added
.
"amt of acid from 23%" + "amt of acid from 12%" = "amt in final mixture"
.23(440) + .12x = .145(440+x)
101.2 + .12x = 63.8 + .145x
37.4 + .12x = .145x
37.4 = 0.025x
1496 liters = x