Question 169164
*[Tex \LARGE 3\tan^{-1}(2x)=\pi] ... Start with the given equation



*[Tex \LARGE \tan^{-1}(2x)=\frac{\pi}{3}] ... Divide both sides by 3



*[Tex \LARGE 2x=\tan(\frac{\pi}{3})] ... Take the tangent of both sides to eliminate the inverse tangent (or arctangent)



*[Tex \LARGE 2x=\sqrt{3}] Take the tangent of *[Tex \LARGE \frac{\pi}{3}] to get {{{sqrt(3)}}}



*[Tex \LARGE x=\frac{\sqrt{3}}{2}] Divide both sides by 2 to isolate x



So the answer is *[Tex \LARGE x=\frac{\sqrt{3}}{2}]