Question 169043
Let x=larger number
And y=the smaller number

Now we are told the following:
x+y=68-------------------------------eq1
x/y=7+4/y  multiply each term by y
x=7y+4 ------------------------------------eq2

Substitute eq2 into eq1 and we get:
7y+4+y=68  subtract 4 from each side
8y=68-4=64  divide each side by 8
y=8-----------------------------the smaller number
Substitute y=8 into eq1:
8+y=68  subtract 8 from each side:
y=60------------------------larger number

CK
60/8=7 with a remainder of 4 or 7+4/8=7 1/2


Hope this helps----ptaylor