Question 169000
Factor:
{{{4a^4b^8c^6 - 49d^8}}} This expression can be written as the difference of squares:
{{{(2a^2b^4c^3)^2 - (7d^4)^2}}}
The difference of squares can be factored thus:
{{{A^2-B^2 = (A-B)(A+B)}}}, so...
{{{4a^4b^8c^6-49d^8 = (2a^2b^4c^3-7d^4)(2a^2b^4c^3+7d^4)}}}