Question 168986
can somebody help me solve this equation: {{{4^(x-x^2)=1/2}}}
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{{{4^(x-x^2)=1/2}}}
{{{2^(2x-2x^2)=2^-1}}}
{{{2x-2x^2 = -1}}}
{{{2x^2 - 2x - 1 = 0}}}
{{{x = 1/2 + sqrt(3)/2}}}
{{{x = 1/2 - sqrt(3)/2}}}