Question 168965
A man 38 years old has a son who is 14 years old. How many years ago was the 
father seven times as old as his son?
:
Let x = no. of year for this to be true
:
38 - x = 7(14 - x)
:
38 - x = 98 - 7x
:
-x + 7x = 98 - 38
:
6x = 60
:
x = 10 yrs ago
;
:
Check solution
38 - 10 = 7(14 - 10)